SOLUTION: How would I go about solving a system of equations with three equations and three variables. 4x-4y-z=38 x+4y-3z=6 -3x+2y-z=-14 Please explain step by step, I would appreci

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: How would I go about solving a system of equations with three equations and three variables. 4x-4y-z=38 x+4y-3z=6 -3x+2y-z=-14 Please explain step by step, I would appreci      Log On


   



Question 148374: How would I go about solving a system of equations with three equations and three variables.
4x-4y-z=38
x+4y-3z=6
-3x+2y-z=-14
Please explain step by step, I would appreciate it. Thank you.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
There are several methods to choose from.
One of them is the substitution method.
1.4x-4y-z=38
2.x%2B4y-3z=6
3.-3x%2B2y-z=-14
You can use eq. 2 to come up with an expression for x in terms of y and z and substitute into eqs. 1 and 3.
2.x%2B4y-3z=6
x=-4y%2B3z%2B6
Now substitute into eq. 1,
1.4x-4y-z=38
1.4%28-4y%2B3z%2B6%29-4y-z=38
1.%28-16y%2B12z%2B24%29-4y-z=38
1.-20y%2B11z%2B24=38
1.-20y%2B11z=14
and eq. 3,
3.-3x%2B2y-z=-14
3.-3%28-4y%2B3z%2B6%29%2B2y-z=-14
3.%2812y-9z-18%29%2B2y-z=-14
3.14y-10z-18=-14
3.14y-10z=4
3.7y-5z=2
Now you've reduce from three variables to two variables.
1.-20y%2B11z=14
3.7y-5z=2
You can again do a substitution to get y in terms of z.
From new eq. 1,
1.-20y%2B11z=14
1.-20y=-11z%2B14
1.y=%2811z-14%29%2F20
Now substitute this value into new eq. 3.
3.7y-5z=2
3.%287%2811z-14%29%2F20%29-5z=2
3.%287%2811z-14%29%29-100z=40
3.%2877z-98%29-100z=40
3.-23z-98=40
3.-23z=138
z=-6
Now go backwards and substitute to find y and then x.
3.7y-5z=2
7y-5%28-6%29=2
7y%2B30=2
7y=-28
y=-4
And finally x,
x=-4y%2B3z%2B6
x=-4%28-4%29%2B3%28-6%29%2B6
x=16-18%2B6
x=4
Your solution is therefore,
(x,y,z,)=(4,-4,-6)