SOLUTION: You can walk 10 miles in the same time that it takes to travel 15 miles by bicycle. If the bike's rate is 3 miles per hour faster than your wlaking rate, fing the average rate for

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Question 148319: You can walk 10 miles in the same time that it takes to travel 15 miles by bicycle. If the bike's rate is 3 miles per hour faster than your wlaking rate, fing the average rate for each.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
You can walk 10 miles in the same time that it takes to travel 15 miles by bicycle. If the bike's rate is 3 miles per hour faster than your walking rate, find the average rate for each.
:
Let x = walking rate
then
(x+3) = biking rate
:
Write a time equation: Time = dist%2Frate
:
Biking time = walking time
15%2F%28%28x%2B3%29%29 = 10%2Fx
Cross multiply
:
15x = 10(x+3)
:
15x = 10x + 30
:
15x - 10x = 30
:
5x = 30
x = 30%2F5
x = 6 mph, that's really fast walking!
then
6 + 3 = 9 mph is the bike rate
:
:
Check solution by finding the time for each:
15/9 = 1.67 hrs
10/6 = 1/67 hrs; confirm our solutions