SOLUTION: Solve 4x^2+20=0

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Question 148306: Solve 4x^2+20=0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

4x%5E2%2B20=0 Start with the given equation.


4x%5E2=0-20 Subtract 20 from both sides.


4x%5E2=-20 Combine like terms on the right side.


x%5E2=%28-20%29%2F%284%29 Divide both sides by 4 to isolate x%5E2.


x%5E2=-5 Reduce.



x=0%2B-sqrt%28-5%29 Take the square root of both sides.


x=sqrt%28-5%29 or x=-sqrt%28-5%29 Break up the expression.


x=i%2Asqrt%285%29 or x=-i%2Asqrt%285%29 Simplify the square root.


So our answers are x=i%2Asqrt%285%29 or x=-i%2Asqrt%285%29