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Question 148266: Here is four questions that I need help with.
1. if log 90=x, then x=
3
2. if [x+2]=5, solve for x
3. given the following linear equations:
2x+3y=10
4x-6y=-28
solve for (x,y) if there is a solution.
4. Multiply the complex numbers (3+2i)(3-2i)
thanks for your help
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! 1. if log 90=x, then x=
3
2. if [x+2]=5, solve for x
3. given the following linear equations:
2x+3y=10
4x-6y=-28
solve for (x,y) if there is a solution.
4. Multiply the complex numbers (3+2i)(3-2i)
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1. I don't know what that 3 means. Ignoring it, the log(90)=1.95424...
If it means the log(90) to some base is 3, then the base is the cube root of 90, or apx 4.4814...
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2. x+2=5
x=3
--------
3. 2x+3y=10
4x-6y=-28
Using determinants
2 3 -10
4 -6 28
x = -1, y = 4
---------------
4. (3+2i)*(3-2i)
= 
= 9 - (-4)
= 13
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