SOLUTION: The sum of two numbers is 73. The second is 7 more than 5 times the first. What are the two numbers?
Can some please help out with this question.
v/r
Jess
Question 148180: The sum of two numbers is 73. The second is 7 more than 5 times the first. What are the two numbers?
Can some please help out with this question.
v/r
Jess Found 2 solutions by Alan3354, stanbon:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The sum of two numbers is 73. The second is 7 more than 5 times the first. What are the two numbers?
Let's call them N1 and N2.
N1 + N2 = 73
N2 = 5*N1 + 7
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Sub for N2 in the 1st equation
N1 + 5*N1+7 = 73
6*N1 + 7 = 73
6*N1 = 66
N1 = 11
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N2 = 73-11 = 62
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It all fits.
You can put this solution on YOUR website! The sum of two numbers is 73. The second is 7 more than 5 times the first. What are the two numbers?
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Using two variables:
EQUATIONS:
x + y = 73
y = 5x + 7
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Substitute the 2nd into the 1st to get:
x + (5x+7) = 73
6x = 66
x = 11
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Substitute into y = 5x+7 to solve for "y":
y = 5*11+7
y = 62
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Using one variable:
Let 1st be "x";
then 2nd = 5x+7
EQUATION:
x + 5x+7 = 73
6x + 7 = 73
6x = 66
x = 11
then y = 62
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Cheers,
Stan H.
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