SOLUTION: 41: 4(3+x)+10= -11(x-6)+1 43:3x+21=-2x+11 45:6x+4=2x whenever i experiance any of these types of questions im not sure how to solve for x when there is an x on both sides of

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Question 148139This question is from textbook algebra: the easy way
: 41: 4(3+x)+10= -11(x-6)+1
43:3x+21=-2x+11
45:6x+4=2x
whenever i experiance any of these types of questions im not sure how to solve for x when there is an x on both sides of the equation. Given that the book that im using does not go over how to do these types of equations im at lost of how to do it, any help trying to solve these equations is greatly appreciated by me, thank you.
-Brian. This question is from textbook algebra: the easy way

Answer by vleith(2983) (Show Source):
You can put this solution on YOUR website!
The way to solve these types of problems is to get all the constants on one side and all the terms with x in them on the other. Then simplfy.
Let's do the first one
41: 4(3+x)+10= -11(x-6)+1
First expand both sides using distribution
12+4x + 10 = -11x + 66 + 1
Now combine like terms
22 + 4x = 67 - 11x
Now get the constants on one side and the x terms on the other
4x + 11x = 67 - 22
Combine like terms again
15x = 55
Now isolate x by diving both sides by 15
x = 55/15 = 11/3
Check you answer by using 11/3 as x in the original problem and verifying that both sides are equal
43 is easier.
3x+21 = -2x + 11
same steps. get constants on one side, x term on the other
3x + 2x = 11 - 21
combine like terms
5x = -10
x = -2
I bet you can do 45 now. Give it a go and ing me if you cant get it