SOLUTION: Factor: x^2+3x+2 and 72-22x+x2 I dont really understand how to factor it. Could someone maybe please explain it to me?

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Question 148099: Factor: x^2+3x+2 and 72-22x+x2
I dont really understand how to factor it. Could someone maybe please explain it to me?

Answer by mangopeeler07(462) About Me  (Show Source):
You can put this solution on YOUR website!
I will explain. whenever the x%5E2 term has a coefficient of 1, you start with (x )(x ).

in x%5E2%2B3x%2B2, everything is positive, so add two addition signs.
(x+ )(x+ ).

Then, find the factors of 2 that add up to 3. That would be 2 and 1. Put them in there.
%28x%2B2%29%28x%2B1%29. You're done.

In 72-22x%2Bx2, first reorder it to x%5E2-22x%2B72. Then you start with
(x )(x ).

everything is not positive, only the first and last, so you add two subtraction signs.
(x- )(x- ).

Then find the two factors of 72 that would add up to 22. That would be 18 and 4. So put them in there.

%28x-4%29%28x-18%29. You're done.

If you want to check them, I would just use the acronym I came up with called SAM. That stands for Squared, Add, Multiply. And it's easy to remember, especially if your name is Sam. Anyway, here's how it works:

Start with:
(x+2)(x+1) and (x-4)(x-18)

Then do your SQUARED terms:
(x+2)(x+1) and (x-4)(x-18)
x%5E2 and x%5E2

Then ADD your other two numbers (keeping in mind the negatives) and attach the variable:
(x+2)(x+1) and (x-4)(x-18)
x%5E2%2B3x and x%5E2-22x

Then MULTIPLY the last two numbers (keeping in mind the negatives):
(x+2)(x+1) and (x-4)(x-18)
x%5E2%2B3x%2B2 and x%5E2-22x%2B72

So now you know how to factor it and how to check your answer!