Question 148090: The equation of the line through (8,6) and (2,) is
a. 5x-3y=22
b. 3/5x + 8/5
c. 3x + 4y = 48
d. -4x + 2y = -16
There is no y coordinate to go with (2,). This is a test question and this is how it was written by the teacher. Could you please help me!
Found 3 solutions by stanbon, oscargut, nerdybill:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The equation of the line through (8,6) and (2,) is
a. 5x-3y=22
b. 3/5x + 8/5
c. 3x + 4y = 48
d. -4x + 2y = -16
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a. (8,6) is a point of the equation
b. that is not an equation
c. (8,6) is a point of the equation
d. (8,6) is not a point of the equation
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Let x = 2 in "a" and in "c" you get the following:
In a: y = -4
In c: y = 21/2
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Cheers,
Stan H.
Answer by oscargut(2103)  (Show Source):
Answer by nerdybill(7384)  (Show Source):
You can put this solution on YOUR website! In this case, since they gave you a single point at (8,6), apply that point to each of the given equations:
a. 5x-3y=22
5(8)-3y=22
40-3y=22
-3y=-18
y = 6
.
b. 3/5x + 8/5
3/5(8) + 8/5
24/5 + 8/5
32/5 (Does NOT equal 6 -- toss it out)
.
c. 3x + 4y = 48
3(8) + 4y = 48
24 + 4y = 48
4y = 24
y = 6
.
d. -4x + 2y = -16
-4(8) + 2y = -16
-32 + 2y = -16
2y = 32
y = 16 (Does NOT equal 6 -- toss it out)
.
Right now, it could either be 'a' or 'c'
a. 5x-3y=22
c. 3x + 4y = 48
.
I would think, at this point, that you could possibly have a typo when you keyed it in. Can you verify that the problem is typed in correctly?
.
Or, if you proceeded, the other piece of information given was (2,)
we could try to plug it into both 'a' and 'c':
a. 5x-3y=22
5(2)-3y=22
10-3y=22
-3y=12
y = -4
.
c. 3x + 4y = 48
3(2) + 4y = 48
6 + 4y = 48
4y = 42
y = 10.5
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