SOLUTION: I am trying to find the solution to the inequality of 6 > - 3x + 5 or 9 £ - 5x + 2 Add 3x to both sides 3x + 6 > 5 Subtract 6 from both sides 3x > -1 X = - 1/3 Next eq

Algebra ->  Inequalities -> SOLUTION: I am trying to find the solution to the inequality of 6 > - 3x + 5 or 9 £ - 5x + 2 Add 3x to both sides 3x + 6 > 5 Subtract 6 from both sides 3x > -1 X = - 1/3 Next eq      Log On


   



Question 147976: I am trying to find the solution to the inequality of
6 > - 3x + 5 or 9 £ - 5x + 2
Add 3x to both sides
3x + 6 > 5
Subtract 6 from both sides
3x > -1
X = - 1/3
Next equation
9 £ - 5x + 2
Add 5x to both sides
5x + 9 £ 2
Subtract 9 from both sides
5x £ -7
X = -7/5
Is the solution to the problem
( - ¥, -7/5] È ( -1/3, ¥)
Because - 7/5 is included so it gets a square bracket but -1/3 gets a parentheses because it is not included and the infinite symbol always gets a parentheses.
Am I getting this correct or am I way off?
Thank you for all your time and help with this as I am trying to prepare for a test.



Found 2 solutions by oscargut, stanbon:
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
You are right

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
6 > - 3x + 5
9 = - 5x + 2
-------------------
I am trying to find the solution to the inequality of
6 > - 3x + 5 or 9 £ - 5x + 2
Add 3x to both sides
3x + 6 > 5
Subtract 6 from both sides
3x > -1
X > - 1/3
----------------------
Next equation
9< - 5x + 2
Add 5x to both sides
5x + 9 < 2
Subtract 9 from both sides
5< -7
X < -7/5
Is the solution to the problem
( - ¥, -7/5] È ( -1/3, ¥)
Because - 7/5 is included so it gets a square bracket but -1/3 gets a parentheses because it is not included and the infinite symbol always gets a parentheses.
Am I getting this correct or am I way off?
-------------
It looks good to me.
Cheers,
Stan H.