SOLUTION: How would you write ln0.2=-1.6 in exponential form and how would you make e^-4=0.0183 into a logarithmic form?

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Question 147847: How would you write ln0.2=-1.6 in exponential form and how would you make e^-4=0.0183 into a logarithmic form?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How would you write ln0.2=-1.6 in exponential form and how would you make e^-4=0.0183 into a logarithmic form?
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ln(0.2) = -1.6
e^(-1.6) = 0.2
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e^-4=0.0183
ln(0.0183) = -4
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Cheers,
Stan H.