SOLUTION: How do you solve y^(-1/3) -3y^(2/3) /y^(-4/3)? No decimals or negative exponents please

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Question 147842: How do you solve y^(-1/3) -3y^(2/3) /y^(-4/3)? No decimals or negative exponents please
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
y^(-1/3) -3y^(2/3) /y^(-4/3)
Factor the numerator to get:
= y^(-1/3)[1 - 3y]/y^(-4/3)
Simplify to get:
= y(1-3y)
Change form:
= y - 3y^2
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Cheers,
Stan H.