SOLUTION: 3√27-3√81+3√75-1/2√36
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Algebra: Radicals -- complicated equations involving roots
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Question 147668
:
3√27-3√81+3√75-1/2√36
Answer by
stanbon(75887)
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3√27-3√81+3√75-1/2√36
= 3*3sqrt3 - 3*9 + 3*5sqrt3 - (1/2)*6
= 9sqrt3 -27 + 15sqrt3 - 3
= 24sqrt(3) - 30
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Cheers,
Stan H.