SOLUTION: 4√50/5-2√27/3+3√48-2√18/3
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Algebra: Radicals -- complicated equations involving roots
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Question 147667
:
4√50/5-2√27/3+3√48-2√18/3
Answer by
stanbon(75887)
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4√50/5-2√27/3+3√48-2√18/3
= [(4*5sqrt2)/5] - [(2*3sqrt2)/3] - [(2*3sqrt2)/3]
= [4sqrt2] - [2sqrt2] - 2sqrt2
= 0
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Cheers,
Stan H.