Remember you cannot take the log of zero or of a negative value. So that means the argument must be greater than zero (i.e. the argument must be positive)
Set the inner expression greater than zero
Add 5 to both sides
Combine like terms on the right side
So that means t must be greater than in order for t to be in the domain
So the domain in set-builder notation is
So here is the domain in interval notation:
Notice if we graph (just replace t with x), we get
notice how the graph never crosses the line . So this graphically verifies our answer.
and we can see that x must be greater than in order to lie on the graph