SOLUTION: The parallel sides of trapezoid ABCD are AD and BC. Given that sides AB, BC, and CD are each half as long as side AD, find the size of angle D.

Algebra ->  Geometry-proofs -> SOLUTION: The parallel sides of trapezoid ABCD are AD and BC. Given that sides AB, BC, and CD are each half as long as side AD, find the size of angle D.       Log On


   



Question 147598: The parallel sides of trapezoid ABCD are AD and BC. Given that sides AB, BC, and CD are each half as long as side AD, find the size of angle D.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!

Length of AB = x
Length of BC = x
Length of CD = x
Length of AD = 2x
Draw two perpendicular lines from BC to AD at points B and C.

These create new line BG and CH, and break up AD into AG, GH, and HD.
The triangles ABG and CDH are right triangles and from the diagram BC=GH=x.
BG=CH
AG=HD
AD=AG%2BGH%2BHD
2x=AG%2Bx%2BHD
2x=AG%2Bx%2BAG
AG=x%2F2
Now you have a right triangle with hypotenuse of x and an adjacent leg of x/2.
From trigonometry,
cos%28A%29=Adj%2FHyp
cos%28A%29=%28x%2F2%29%2Fx
cos%28A%29=1%2F2
A=60
Since ABG and CDH are identical, angle A and angle D are the same.
D=60