Question 147424: Please answer this question. I do not know how to solve a problem to the -2/3 power. What is the answer to 27^(-2/3) (-2/3) being the exponent
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! You should review your rules on "exponent".
.
when you see:
4^(1/2)
this is equivalent to
sqrt(4) = 2
.
when you see:
27^(1/3)
this is equivalent to
cubert(27) = 3
.
So, for your problem:
27^(-2/3)
Consider the (1/3) part of the exponent first. So, the cube root of 27 is 3 therefore you would have:
27^(-2/3) = 3^(-2)
.
Now, when see a "negative" power, you can "move it":
If it was in the numerator, move it to the denominator.
If it was in the denominator, move it to the numerator.
.
So, now we have:
3^(-2) = 1/[3^2] = 1/9
.
Your solution is:
27^(-2/3) = 1/9
|
|
|
