SOLUTION: Three consecutive integers such that the sum of the first, twice the second and three times the third is 80. What are the integers?
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Question 147420
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Three consecutive integers such that the sum of the first, twice the second and three times the third is 80. What are the integers?
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integers:
a
a+1
a+2
Convert words to symbols:
a+2(a+1)+3(a+2)=80
6a+8=80
6a=72
a=12
So the numbers are 12, 13, and 14.