SOLUTION: State the domain of m(x)= 5/x^2-9 Help???

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Question 147400: State the domain of m(x)= 5/x^2-9
Help???

Answer by mangopeeler07(462) About Me  (Show Source):
You can put this solution on YOUR website!
The domain of x would be whatever x is that won't make the denominator zero. So let's start like this: m%28x%29=+5%2Fx%5E2-9. Now since the domain of x is whatever x is that won't make the denominator zero, let's focus just on the denominator. First factor it. It is the difference between two perfect squares, so it is %28x-3%29%28x%2B3%29. Now take each expression separately as x-3 and x%2B3. Set them both equal to zero. x-3=0 and x%2B3=0. Solve both of them and get 3 and -3. These values for x are what x is to make the denominator zero. Therefore, these values are what x cannot be in this function. So the domain of x would be any value for x except those two. Domain: all x except 3 and -3.