SOLUTION: Ok, with this particular question I did it again and again, but my answer just doesn't add up. This is Transforming equations...Again. The problem is 3(x-5)+7=16, and I got 3x=38

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Ok, with this particular question I did it again and again, but my answer just doesn't add up. This is Transforming equations...Again. The problem is 3(x-5)+7=16, and I got 3x=38      Log On


   

Question 147328This question is from textbook algebra
: Ok, with this particular question I did it again and again, but my answer just doesn't add up. This is Transforming equations...Again. The problem is
3(x-5)+7=16, and I got 3x=38
The way I solved it was this way: 3(x-5)+7=16 3x-15+7=16 3x-22=16 3x-22+22=16+22 which equals to 3x=38, but I have the feeling it's wrong. Please help me, thank you=) This question is from textbook algebra

Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
3(x-5)+7=16
3(x-5) = 9
x-5 = 3
x = 8
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Cheers,
Stan H.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

3%28x-5%29%2B7=16 Start with the given equation.


3x-15%2B7=16 Distribute.


3x-8=16 Combine like terms on the left side.


3x=16%2B8 Add 8 to both sides.


3x=24 Combine like terms on the right side.


x=%2824%29%2F%283%29 Divide both sides by 3 to isolate x.


x=8 Reduce.


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Answer:

So the answer is x=8