You can put this solution on YOUR website! 2x(3+4x)-4x(3-6x)>=10
6x+8x^2-12x+24x^2-10>=0
32x^2-6x-10>=0
2(16x^2-3x-5)>=0
using the quadratic equation: we get:
x=(3+-sqrt[-3^2-4*16*-5])/2*16
x=(3+-sqrt[9+320])/32
x=(3+-sqrt329)/32
x=(3+-18.14)/32
x=(3+18.14)/32
x=21.14/32
x=.66 answer.
x=(3-18.14)/32
x=-15.14/32
x=-.473 answer.