SOLUTION: the length of an rectangle is fixed at 20 cm. what widths will make the perimiter greater than 86 cm?

Algebra ->  Rectangles -> SOLUTION: the length of an rectangle is fixed at 20 cm. what widths will make the perimiter greater than 86 cm?      Log On


   

Question 147249: the length of an rectangle is fixed at 20 cm. what widths will make the perimiter greater than 86 cm?
Answer by psbhowmick(878) About Me  (Show Source):
You can put this solution on YOUR website!
Perimeter of a rectangle = 2 x (Length + Width)

Let width = w cm.
Then the perimeter = 2(20 + w) = (40 + 2w) cm.
By problem this perimeter has to be greater than 86 cm.
So, 40 + 2w > 86.
2w > 86 - 40
2w > 46
w > 23

So, the width has to be more than 23 cm.