SOLUTION: A rancher has some sheep and ostriches. His young daughter observed that the animals have a total of 60 eyes and 86 feet. How many animals of each type does the rancher have?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: A rancher has some sheep and ostriches. His young daughter observed that the animals have a total of 60 eyes and 86 feet. How many animals of each type does the rancher have?      Log On


   



Question 147190: A rancher has some sheep and ostriches. His young daughter observed that the animals have a total of 60 eyes and 86 feet. How many animals of each type does the rancher have?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let s= number of sheep
Let b= number of ostriches
4s= number of legs that sheep have
2b= number of legs that ostriches have
2%2A%28s+%2B+b%29= number of eyes sheep and ostriches together have
4s+%2B+2b+=+86
Divide both sides by 2
2s+%2B+b+=+43
and
2s+%2B+2b+=+60
Divide both sides by 2
s+%2B+b+=+30
b+=+30+-+s
Substitute this in the other equation
2s+%2B+b+=+43
2s+%2B+30+-+s+=+43
s+=+13
b+=+30+-+s
b+=+30+-+13
b+=+17
There are 13 sheep and 17 ostriches
check:
4s+%2B+2b+=+86
4%2A13+%2B+2%2A17+=+86
52+%2B+34+=+86
86+=+86
OK