Question 147173: pls answer this...Two-point form equation... Find an equation of a line given two points and check result(with solution)
1.(0,2)(4,3)
2.(3,-5)(-2,1)
3.(-1,4)(-6,0)
4.(5,-1)(-3,-2)
5.(1/4-5)(2/3,1/2)
pls answer...ASAP...
tnx!!
Answer by mangopeeler07(462)   (Show Source):
You can put this solution on YOUR website! The first one is the easiest, so I'll start there. Heck, it's the beginning anyway. The equation of the line should be in y=mx+b form, with b being your y intercept (whatever y is when x is zero, like y intercepted the ball before x could score) and m is your slope. to get the slope, take the coordinates of two points on the line. Then set it up like this  . That doesn't mean double y and x, that just means the two different points for y and x that you have. So don't multiply. Plug in the corressponding values (it doesn't matter which order as long as you are consistent). It should look like  . Simplify it and get  or 1/4. That is your slope. You are given that your y intercept is 2, because when x is zero, y is 2. So that is your intercept. plug this into y=mx+b and get  . That is your equation for the line. repeat these steps for the other lines.--------(When the intercept is not given to you, just use the slope. The slope is rise over run, so the numerator is how much y should increase or decrease, and the denominator is how much x should increase or decrease. Play around with it until x is zero and see what y is. If x is not zero from that, graph the line with the points you know and estimate what y is when x is zero.)
|
|
|
