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Question 147157: CAN SOMEONE HELP ME GRAPH THE INEQUALITY ON A PLANE FOR
5X + 6Y <30
Answer by mangopeeler07(462)   (Show Source):
You can put this solution on YOUR website! In order to solve this problem and graph it, you need to first get it into  form. (b=30) Start with 5x +6y<30. subtract 5x from each side to get  Then divide each side by 6 and get  (The inequality sign flips when you divide.) Then to graph it, act as if it is a simple line with the equation  It should look like this:
| Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc |
Equation  describes a sloping line. For any
equation ax+by+c = 0, slope is  .- X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 30/5 = 6.
- Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 30/6 = 5.
- Slope is -5/6 = -0.833333333333333.
- Equation in slope-intercept form: y=-0.833333333333333*x+5.
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Now to graph  is very simple once you have its reference line (above). Simply erase parts of the line (in other words, leave the line dotted so that it actually looks like a reference line), and then shade in the rest of the graph above the line. (that shows that the area in question does not include the line, so make sure that it is dotted. otherwise, you are saying that y is more than or equal to...not simply more than...)And there you have it. It should just look like the above graph with some shading above it. No sweat, right?
If you still need help, visit my lesson: http://www.algebra.com/algebra/homework/Graphs/Inequalities-Made-Easy.lesson
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