Question 147135: Find the verex and intercepts. Sketch the graph
g(x) = x^2 + -6
Found 3 solutions by edjones, checkley77, Edwin McCravy:
Answer by edjones(8007)   (Show Source):
You can put this solution on YOUR website! The y intercept is -6
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x^2-6=0
x^2=6
x=-sqrt(6), x=sqrt(6) the x intercepts.
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The vertex at x=sqrt(6)-sqrt(6)=0
The vertex at y=-6 special case.
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Ed
Answer by checkley77(12844)  (Show Source):
Answer by Edwin McCravy(20077)  (Show Source):
You can put this solution on YOUR website! Edwin's solution:
Find the verex and intercepts. Sketch the graph
The vertex formula:
The graph of
has the vertex ( ,  ), where 
Therefore
can be written as
So we apply the vertex formula:
 ,  ,  , 
so the vertex is
(, ) =
( ,  ) = ( ,  )
To find the y-intercept, we substitute 
So the y-intecept is ( , ), which just happens
to, in this case, be the same point as the vertex.
To find the x-intercepts, we we substitute 
 = ±
Since the square root of 6 is about  ,
the two x intercepts are about ( , ) and (, )
So we plot those two points, as well as:
vertex: (, )
and
y-intercept: (, ) [Which in this case just
happens to be the same point as the vertex.]
Edwin
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