SOLUTION: I need help on how to solve this word problem. (((The area of triangle is 462m^2 if the altitude is 2m longer than half the base find the altitude and base of the triangle.)))

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Question 147090: I need help on how to solve this word problem.
(((The area of triangle is 462m^2 if the altitude is 2m longer than half the base find the altitude and base of the triangle.)))
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
AREA=B*H/2
462=B(B/2+2)/2
462=[B(B+4)/2]/2
462=(B^2+4B)/2*1/2
462=(B^2+4B)/4
4*462=B^2+4B
1,848=B^2+4B
B^2+4B-1,848=0
USING THE QUADRATIC EQUATION: x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
B=(-4+-SQRT4^2-4*1*-1848})/281
B=(-4+-SQRT[16+7,392])/2
B=(-4+-SQRT7,408)/2
B=(-4+-86.07)/2
B=(-4+86.07)/2
82.07/2
B=41.03 FOR THE LENGTH OF THE BASE
H=2+41.03/2=2+20.52=22.52 FOR THE HEIGHT
PROOF
462=41.03*22.52/2
462~462