SOLUTION: The length of a rectangle is two more than three times the width.If the perimeter is 100, find the length and width of the rectangle.
thank you
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-> SOLUTION: The length of a rectangle is two more than three times the width.If the perimeter is 100, find the length and width of the rectangle.
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You can put this solution on YOUR website! The length of a rectangle is two more than three times the width.If the perimeter is 100, find the length and width of the rectangle.
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Let W = width of rectangle
then from "length of a rectangle is two more than three times the width" we get
3W+3 = length of rectangle
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Our equation comes from "the perimeter is 100"
We "should" already know that the perimeter of a rectangle is
L + L + W + W
or
2L + 2W
or
2(L+W)
.
Our equation is then:
2(L+W) = 100
But, we said (from the top) that L = 3W+3 so we substitute it in thus:
2(3W+3+W) = 100
2(4W+3) = 100
8W + 6 = 100
8W = 94
W = 11.75 (this is the width of the rectangle)
3W+3 = 3(11.75)+3 = 38.25 (this is the length of the rectangle)