SOLUTION: Solve following word problems:
A: One number is 3 times another. If the sum of their reciprocals is 1/6, find the two numbers.
B: If one-third of a number is subtracted from
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A: One number is 3 times another. If the sum of their reciprocals is 1/6, find the two numbers.
B: If one-third of a number is subtracted from
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Question 147019: Solve following word problems:
A: One number is 3 times another. If the sum of their reciprocals is 1/6, find the two numbers.
B: If one-third of a number is subtracted from three-fourths of that number, the difference is 15. What is the number? Found 2 solutions by edjones, 24HoursTutor.com:Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! a=3b
1/a + 1/b = 1/6
1/3b + 1/b = 1/6 substitute
2+6=b Multiply each side by 6b to eliminate fractions.
b=8
a=24
.
Let x be the number.
3x/4 - x/3 = 15
9x-4x=180 Multiply each side by 12 to eliminate fractions.
5x=180
x=36
.
Ed
You can put this solution on YOUR website! A)
Let one number be x
and the other number be y
We know that y = 3x
Reciprocal of x = 1/x
Reciprocal of y = 1/y
Sum of reciprocal = 1/6
So, we have
1/x + 1/y = 1/6
Now substituting 3x in place of y we get :
1/x+1/3x = 1/6
(3+1)/3x = 1/6
4/3x = 1/6
4X6=1X3x
24=3x
x=24/3
x=8
y=3x=3X 8 =24
Answer: The two numbers are 8 and 24.
B)
Let us assume the number to be x. We can write the information given in the question as the following equation :
1x/3 - 3x/4 = 15
(4x-9x)/12 = 15
-5x/12 = 15
-5x = 15 X 12
-5x = 180
x = 180/-5
x = -36
Answer: The number is -36
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