SOLUTION: The game commission introduces 50 buffalo into newly acquired state game lands. The population of the herd is given by N= (10 (5+3t))/(1+.04t)=(30t+50)/(.04t+1) or (30t+50)/(

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: The game commission introduces 50 buffalo into newly acquired state game lands. The population of the herd is given by N= (10 (5+3t))/(1+.04t)=(30t+50)/(.04t+1) or (30t+50)/(      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 146973: The game commission introduces 50 buffalo into newly acquired state game lands. The population of the herd is given by

N= (10 (5+3t))/(1+.04t)=(30t+50)/(.04t+1) or (30t+50)/(.04t+1)
where t is time in years. The limiting size of the herd as time increases is given by the horizontal asymptote. What is the limiting size of the herd?
Thank you

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The game commission introduces 50 buffalo into newly acquired state game lands. The population of the herd is given by
N= (10 (5+3t))/(1+.04t)=(30t+50)/(.04t+1) or (30t+50)/(.04t+1)
where t is time in years. The limiting size of the herd as time increases is given by the horizontal asymptote. What is the limiting size of the herd?
--------
The highest power term in the numerator is 30t
The highest power term in the denominator is 0.04t
-----------
The horizontal asymptote is N = 30/0.4 = 75
------------
The limiting size is 75
====================
Cheers,
Stan H.