SOLUTION: a painting is 3 inches longer than it is wide. it is set in a rectangular border that is 2 inches wider than the painting on each side. if the area of the border is 100 inch^2 what
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Question 146825: a painting is 3 inches longer than it is wide. it is set in a rectangular border that is 2 inches wider than the painting on each side. if the area of the border is 100 inch^2 what are the dimensions of the painting Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! L*w=A
L=w+3 for painting
w*(w+3)=w^2+3w Area of the painting.
(w+2)(w+5)=w^2+7w+10 Area of border and painting combined.
w^2+7w+10-(w^2+3w)=100
w^2+7w+10-w^2-3w=100
4w+10=100
4w=90
w=22.5"
L=25.5"
.
Ed
