Question 146817This question is from textbook
: USe slopes to show that the square with vertices at (-2,5), (4,5), (4,-1) and
(-2,-1) has diagonals that are perpendicular
This question is from textbook
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Opposite corners are (-2,5) and (4,-1),
and (-2,-1) and (4,5).
Find the slope m of the lines connecting opposite corners.
----------------
(-2,5) and (4,-1)
m1 = (y2-y1)/(x2-x1)
m1 = (-1-5)/(4+2)
m1 = -6/6 = -1
-------------
(-2,-1) and (4,5)
m2 = (5 - (-1))/(4 -(-2))
m2 = 6/6 = +1
Since the slopes are negative inverses, they're perpendicular.
|
|
|
