|  | 
| 
 
 
| Question 146550:  Question 1: Find the slope and the y intercept of the line. Write fractional answers in lowest terms.
 9y+7x+7=14+7x
 Question 2: Find the slpe if it exits of the line containing the pair of points.
 (1,5) and (4,-3)
 The sllope m= ?
 Question 3: Find an equation of the line containing the given peir of points.
 (-5,-3) and (-1,-2)
 The equation of the line is y?
 
 Answer by aswathytony(47)
      (Show Source): 
You can put this solution on YOUR website!  1)    9y + 7x +7 = 14 +7x 9y +7x - 7x +7 -14 =0
 9y -7 =0 ; 9y= 7
 y = 7/9   ; This is the equation of a horizontal line of the form y=b. here
 slope m=0. y -intercept = 7/9.
 2)slope of the line containing points (x1,y1) & (x2,y2) is y2-y1/x2-x1
 slope of line containing (1,5) & (4,-3)= (-3 - 5) /(4-1)
 = -8/3
 3) equation of line containing (x1,y1) & (x2, y2)
 x-x1/x2-x1 = y-y1/y2-y1
 equation of line containing (-5,-3) &(-1,-2)
 x-(-5)/-1 - (-5) = y - (-3)/-2 - (-3)
 x+5/4 = y+3/1
 x + 5 = 4 (y+3)
 x+5 =4y +12
 x- 4y +5 -12 =0.
 x - 4y -7=0. this is the equation of the line.
 or      -4y = -x +7
 y = -x/-4 + 7/-4
 y= x/4 -7/4.
 here slope = 1/4 and y intercept =-7/4.
 
 
 | 
  
 | 
 |  |  |