SOLUTION: If anyone could help me out with these graphing questions, I would REALLY appreciate it! I'm completely lost! Thank you so much! Graph the equation: a) y= 3x + 2 b) y= -x

Algebra ->  Rational-functions -> SOLUTION: If anyone could help me out with these graphing questions, I would REALLY appreciate it! I'm completely lost! Thank you so much! Graph the equation: a) y= 3x + 2 b) y= -x       Log On


   



Question 146533: If anyone could help me out with these graphing questions, I would REALLY appreciate it! I'm completely lost! Thank you so much!
Graph the equation:
a) y= 3x + 2
b) y= -x
c) y= 1/2x + 2
d) y= x+2
e) y= -1/4x - 1
f) y= 3x+3
g) -3y= 6x
h) -5x + 3y -15 = 0
i) 2x + y = 3
j) x-2y+2=0
If you could just show me how to do a few of these (like how to start them out) I think I'd be able to figure it out. I just wanted to give some examples of what I'm doing.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Anytime you want to graph an equation, you NEED to solve for "y" first. So for problems g, h, i, and j, you need to solve for y

I'll do the first 3 to get you started.


a)



Looking at y=3x%2B2 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=3 and the y-intercept is b=2


Since b=2 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is 3, this means:

rise%2Frun=3%2F1


which shows us that the rise is 3 and the run is 1. This means that to go from point to point, we can go up 3 and over 1



So starting at , go up 3 units


and to the right 1 unit to get to the next point



Now draw a line through these points to graph y=3x%2B2

So this is the graph of y=3x%2B2 through the points and





b)



Looking at y=-x we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=-1 and the y-intercept is b=0 note: y=-x really looks like y=-x%2B0


Since b=0 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is -1, this means:

rise%2Frun=-1%2F1


which shows us that the rise is -1 and the run is 1. This means that to go from point to point, we can go down 1 and over 1



So starting at , go down 1 unit


and to the right 1 unit to get to the next point



Now draw a line through these points to graph y=-x

So this is the graph of y=-x through the points and





c)


Looking at y=%281%2F2%29x%2B2 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=1%2F2 and the y-intercept is b=2


Since b=2 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is 1%2F2, this means:

rise%2Frun=1%2F2


which shows us that the rise is 1 and the run is 2. This means that to go from point to point, we can go up 1 and over 2



So starting at , go up 1 unit


and to the right 2 units to get to the next point



Now draw a line through these points to graph y=%281%2F2%29x%2B2

So this is the graph of y=%281%2F2%29x%2B2 through the points and