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Question 146459: A plane is flying a 3547-mile trip from City A to City B. It is flying with a 60-mph tailwind. The flight's point of no return is the point at which the flight time required to return to City A is the same as the time required to continue to City B. If the speed of the plane in still air is 350 mph, how far from City A is the point of no return? Round to the nearest mile.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A plane is flying a 3547-mile trip from City A to City B.
It is flying with a 60-mph tailwind.
The flight's point of no return is the point at which the flight time required to return to City A is the same as the time required to continue to City B.
If the speed of the plane in still air is 350 mph, how far from City A is the point of no return?
Round to the nearest mile.
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With the wind DATA from A:
Rate = 350+60 = 410 mph ; distance = "x" miles ; time = d/r = x/410 hrs.
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Against the wind DATA:
Rate=350-60 = 290 mph; distance = "3547-x" miles ; time = d/r = (3547-x)/290 hrs
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EQUATION:
time = time
x/410 = (3547-x)/290
290x = 410*3547-410x
700x = 1454270
x = 2077.53 miles
3547-2077.53 = 1469.47 miles from A (pt. of no return)
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Cheers,
Stan H.
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