SOLUTION: A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null

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Question 146432: A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are:
Day of the Week Number Absent
Monday 12
Tuesday 9
Wednesday 11
Thursday 10
Friday 9
Saturday 9

7. What is the expected frequency?
A. 9
B. 10
C. 11
D. 12

8. What is the calculated value of chi-square?
A. 1.0
B. 0.5
C. 0.8
D. 8.0

9. What is your conclusion?
A. Absenteeism is evenly distributed throughout the week.
B. Absenteeism is not evenly distributed throughout the week.
C. I cannot say anything about absenteeism based on my statistics.
D. Absenteeism is increasing throughout the week.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are:
Day of the Week Number Absent
Monday 12
Tuesday 9
Wednesday 11
Thursday 10
Friday 9
Saturday 9
7. What is the expected frequency?
(1/6)60 = 10
A. 9
B. 10
C. 11
D. 12
----------------
8. What is the calculated value of chi-square?
A. 1.0
B. 0.5
C. 0.8
D. 8.0
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The Chi-Sq value is 0.387332..
The corresponding p-value is 1
Comment: I think your question meant to ask about the p-value.
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9. What is your conclusion?

A. Absenteeism is evenly distributed throughout the week.
B. Absenteeism is not evenly distributed throughout the week.
C. I cannot say anything about absenteeism based on my statistics.
D. Absenteeism is increasing throughout the week.
Ans: B because the p-value is less than 5%
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Cheers,
Stan H.