Question 146428: In a three-digit lottery, each of the three digits is supposed to have the same probability of occurrence
(counting initial blanks as zeros, e.g., 32 is treated as 032). The table shows the frequency
of occurrence of each digit for 90 consecutive daily three-digit drawings. (a) Make a bar chart and
describe it. (b) Calculate expected frequencies for each class. (c) Perform the chi-square test for a
uniform distribution. At α = .05, can you reject the hypothesis that the digits are from a uniform
population? Lottery3
Digit Frequency
0 33
1 17
2 25
3 30
4 31
5 28
6 24
7 25
8 32
9 25
Total 270
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! In a three-digit lottery, each of the three digits is supposed to have the same probability of occurrence (counting initial blanks as zeros, e.g., 32 is treated as 032).
The table shows the frequency of occurrence of each digit for 90 consecutive daily three-digit drawings.
(a) Make a bar chart and describe it.
Can't do that on this site.
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(b) Calculate expected frequencies for each class.
270/10 = 27 for each digit
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(c) Perform the chi-square test for a uniform distribution.
At α = .05, can you reject the hypothesis that the digits are from a uniform
population?
chi-Sq = 4.16
p-value = 0.9
Conclusion: Since the p-value is greater than 5%, reject the null hypothesis which states that the distribution is uniform.
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Lottery3
Digit Frequency
0 33
1 17
2 25
3 30
4 31
5 28
6 24
7 25
8 32
9 25
Total 270
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