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Question 146377: Find the slope of a line containing these points.
(5,-2) & (-3,2)
Pleas must show all work! :)
Answer by aswathytony(47)   (Show Source):
You can put this solution on YOUR website! Equation of line passing through two points ( x1, y1) & (x2, y2) is
x - x1/x2 - x1 = y - y1 / y2 - y1.
applying above formula in given question
equation of line passing through (5, -2) & (- 3 , 2) is
x - 5 /-3 - 5 = y - (-2) / 2 - (-2)
x - 5 /(-8) = y + 2 / 4
cross multiplying, we get
4 ( x - 5) = -8 ( y + 2 )
4x - 20 = -8y -16
4x + 8y -4 = 0, this is the equation of line.
to find the slope, write the equation in slope -intercept form i.e. y = mx+c.
4x + 8y -4 =0
8y = - 4x +4
y = -4x/8 + 4 /8
y = -x/2 + 1/2.
this is of slope intercept form,slope m= -1/2.
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