SOLUTION: Please help.
Sky divers. Bob and Betty simultaneously jump from two airplanes at different altitudes. Bob’s altitude t seconds after leaving the plane is -16t^2 + 6600 feet.
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-> SOLUTION: Please help.
Sky divers. Bob and Betty simultaneously jump from two airplanes at different altitudes. Bob’s altitude t seconds after leaving the plane is -16t^2 + 6600 feet.
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Question 146370: Please help.
Sky divers. Bob and Betty simultaneously jump from two airplanes at different altitudes. Bob’s altitude t seconds after leaving the plane is -16t^2 + 6600 feet. Betty’s altitude t seconds after leaving the plane is -16t^2 + 7400 feet. Write a polynomial that represents the difference between their altitudes t seconds after leaving the planes. What is the difference between their altitudes 3 seconds after leaving the planes?
You can put this solution on YOUR website! Bob’s altitude t seconds after leaving the plane is -16t^2 + 6600 feet. Betty’s altitude t seconds after leaving the plane is -16t^2 + 7400 feet. Write a polynomial that represents the difference between their altitudes t seconds after leaving the planes. What is the difference between their altitudes 3 seconds after leaving the planes?
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Bob's altitude after 3 seconds:
a(t) = -16t^2+6600 =
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Betty's altitude after 3 seconds:
b(t) = -16t^2+ 7400
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Difference polynomial
h(t) = b(t)-a(t) = 800 ft
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After 3 seconds the difference is 800 ft.
It continues to be 800 ft. till Bob hits the ground or releases his parachute.
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Cheers,
Stan H.
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