SOLUTION: What are the zero(s) for this equation: 4(x+6)^2-8=-4 a)x={-5} b)x={-5,-7} c)x={-5,0} d)x={5,-7}

Algebra ->  Equations -> SOLUTION: What are the zero(s) for this equation: 4(x+6)^2-8=-4 a)x={-5} b)x={-5,-7} c)x={-5,0} d)x={5,-7}      Log On


   

Question 146281: What are the zero(s) for this equation:
4(x+6)^2-8=-4
a)x={-5}
b)x={-5,-7}
c)x={-5,0}
d)x={5,-7}
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
4(x+6)^2-8=-4
then 4(x+6)^2=4
then (x+6)^2=1
then x+6=1 or x+6=-1
then x=-5 or x=-7
then
option b) is the correct