SOLUTION: At Gwens garage sale, all books were one price, and all magazines were another. Harriet bought 4 books and 3 magazines for $1.45 and June bought 2 books and 5 magazines for $1.25
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-> SOLUTION: At Gwens garage sale, all books were one price, and all magazines were another. Harriet bought 4 books and 3 magazines for $1.45 and June bought 2 books and 5 magazines for $1.25
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Question 146119: At Gwens garage sale, all books were one price, and all magazines were another. Harriet bought 4 books and 3 magazines for $1.45 and June bought 2 books and 5 magazines for $1.25 What was the price of a book and what was the price of a magazine? Found 2 solutions by oscargut, josmiceli:Answer by oscargut(2103) (Show Source):
You can put this solution on YOUR website! Let x the price of the books and
y the price of the magazines
Harriet bought 4 books and 3 magazines for $1.45
then 4x+3y=1.45
June bought 2 books and 5 magazines for $1.25
then 2x+5y=1.25
system is:
4x+3y=1.45
2x+5y=1.25 (-2)
4x+3y=1.45
-4x-10y=-2.5
adding bot equations:
-7y=-1.05
y = 0.15
using first eq
4x+3(0.15)=1.45
4x=1
x=0.25
Solution:
The price of a book is 0.25
The price of a magazine is 0.15
You can put this solution on YOUR website! Let = price of books
Let = price of magazines
(note prices are in cents)
multiply 2nd equation by and subtract
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The books are 25 cent each and magazines are 15 cents each
check:
OK
