SOLUTION: {{{-2k^0-4k+6(-k-2^0)-(-5k)=-(2-5)k-4k }}}

Algebra ->  Expressions-with-variables -> SOLUTION: {{{-2k^0-4k+6(-k-2^0)-(-5k)=-(2-5)k-4k }}}      Log On


   

Question 146104This question is from textbook Saxon Algebra 1
: -2k%5E0-4k%2B6%28-k-2%5E0%29-%28-5k%29=-%282-5%29k-4k+ This question is from textbook Saxon Algebra 1

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
-2k^0-4k+6(-k-2^0)-(-5k)=-(2-5)k-4k
-2-4k-6k-6+5k=-(-3k)-4k Any number to ^0=1.
-5k-8=3k-4k
-5k-8=-k
-4k=8
k=-2
.
Ed