SOLUTION: how would i do this? A box of 6 coins (penny, nickel, dime or quarter) worth $0.67 is shaken. What is the probability that a nickel is drawn first and then a quarter? Assume no re

Algebra ->  Probability-and-statistics -> SOLUTION: how would i do this? A box of 6 coins (penny, nickel, dime or quarter) worth $0.67 is shaken. What is the probability that a nickel is drawn first and then a quarter? Assume no re      Log On


   

Question 146099: how would i do this? A box of 6 coins (penny, nickel, dime or quarter) worth $0.67 is shaken. What is the probability that a nickel is drawn first and then a quarter? Assume no replacement and that all coins are equally likely.

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
The first thing you need to do is figure out what coins are in the box.
You are given 6 coins and a total of $0.67. The only combination of 6 coins that yields $0.67 is
2 quarters
1 dime
1 nickel
2 pennies

Now you are asked to draw two coins and see what the chances are those two coins are a nickel and then a quarter.
Chances of drawing a nickel first are 1 in 6 1%2F6
Chances of drawing a quarter from the coins left in the box after the nickel was drawn is 2 in 5 2%2F5
The chances of getting a nickel and then a quarter is
%281%2F6%29+%2A+%282%2F5%29 = 2%2F30 = 1%2F15