SOLUTION: Factor completely: x^2 + 9x + 8

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Question 145892: Factor completely:
x^2 + 9x + 8

Found 2 solutions by scott8148, jim_thompson5910:
Answer by scott8148(6628) About Me  (Show Source):
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at x%5E2%2B9x%2B8 we can see that the first term is x%5E2 and the last term is 8 where the coefficients are 1 and 8 respectively.

Now multiply the first coefficient 1 and the last coefficient 8 to get 8. Now what two numbers multiply to 8 and add to the middle coefficient 9? Let's list all of the factors of 8:



Factors of 8:
1,2,4,8

-1,-2,-4,-8 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 8
1*8
2*4
(-1)*(-8)
(-2)*(-4)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to 9? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 9

First NumberSecond NumberSum
181+8=9
242+4=6
-1-8-1+(-8)=-9
-2-4-2+(-4)=-6



From this list we can see that 1 and 8 add up to 9 and multiply to 8


Now looking at the expression x%5E2%2B9x%2B8, replace 9x with x%2B8x (notice x%2B8x adds up to 9x. So it is equivalent to 9x)

x%5E2%2Bhighlight%28x%2B8x%29%2B8


Now let's factor x%5E2%2Bx%2B8x%2B8 by grouping:


%28x%5E2%2Bx%29%2B%288x%2B8%29 Group like terms


x%28x%2B1%29%2B8%28x%2B1%29 Factor out the GCF of x out of the first group. Factor out the GCF of 8 out of the second group


%28x%2B8%29%28x%2B1%29 Since we have a common term of x%2B1, we can combine like terms

So x%5E2%2Bx%2B8x%2B8 factors to %28x%2B8%29%28x%2B1%29


So this also means that x%5E2%2B9x%2B8 factors to %28x%2B8%29%28x%2B1%29 (since x%5E2%2B9x%2B8 is equivalent to x%5E2%2Bx%2B8x%2B8)


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Answer:

So x%5E2%2B9x%2B8 factors to %28x%2B8%29%28x%2B1%29