SOLUTION: 1) Given the formula f(a+h)-f(a)/h
(2a^2+4ah+2h^2+4a+4h+5)-(2a^2+4a+5)/h
2) Determine the domain of g(x)=4/x-9, h(x)=6/(x-5)(x-3)
The answers I got were
All R:x=/-9, R:x=
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-> SOLUTION: 1) Given the formula f(a+h)-f(a)/h
(2a^2+4ah+2h^2+4a+4h+5)-(2a^2+4a+5)/h
2) Determine the domain of g(x)=4/x-9, h(x)=6/(x-5)(x-3)
The answers I got were
All R:x=/-9, R:x=
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Question 145845: 1) Given the formula f(a+h)-f(a)/h
(2a^2+4ah+2h^2+4a+4h+5)-(2a^2+4a+5)/h
2) Determine the domain of g(x)=4/x-9, h(x)=6/(x-5)(x-3)
The answers I got were
All R:x=/-9, R:x=/5,-3
3)Given -2x^2-3x+4=0 Use the quadratic formula to solve for the roots.
4)given h(x)=(3x+2. for x>=0)
(5x-1. for x<0)
find h(8) and h(-6)
You can put this solution on YOUR website! 1) Given the formula [f(a+h)-f(a)]/h
[(2a^2+4ah+2h^2+4a+4h+5)-(2a^2+4a+5)]/h
= [4ah + 2h^2 +4h]/h
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Comment: You did not post the function you are working with
but there should not be a 2h^2 term in f(a+h)
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2) Determine the domain of the following:
g(x)=4/(x-9)
Domain: All Real Numbers except x = 9
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h(x)=6/(x-5)(x-3)
Domain: All Real Numbers except x = 5 and x = 3
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3)Given -2x^2-3x+4=0 Use the quadratic formula to solve for the roots.
x = [3 +- sqrt(9-4*-2*4)]/-4
x = [3 +- sqrt(41)]/-4
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4)given h(x)=
(3x+2. for x>=0)
(5x-1. for x<0)
find h(8) = 3*8+2 = 26
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and h(-6) = 5*-6-1 = -31
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Cheers,
Stan H.
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