SOLUTION: 2x^2+16x+24 over 3x^2 divided by 1 over x+6

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Question 145844: 2x^2+16x+24 over 3x^2 divided by 1 over x+6
Answer by Electrified_Levi(103) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, Hope I can help,
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2x^2+16x+24 over 3x^2 divided by 1 over x+6
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%28%282x%5E2%2B16x%2B24%29%2F+3x%5E2%29%2F+%281%2F%28x%2B6%29%29+
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First, we will change the division to multiplication(we will flip the bottom fraction, and multiply it by the top fraction
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+%281%2F%28x%2B6%29%29+=+%28x%2B6%29%2F1+
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%28%282x%5E2%2B16x%2B24%29%2F+3x%5E2%29%2A+%28%28x%2B6%29%2F1%29+
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%282x%5E2%2B16x%2B24%29%28x%2B6%29%2F+3x%5E2%281%29+
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We will multiply the top numbers, and then the bottom numbers together
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%282x%5E3+%2B+28x%5E2+%2B+120x+%2B+144%29%2F3x%5E2+
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You can't reduce it so,
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%282x%5E3+%2B+28x%5E2+%2B+120x+%2B+144%29%2F3x%5E2+ is your answer
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Hope I helped, Levi