SOLUTION: Please help me solve this problem
3^x+4=5^x-1
(x+4)log3=(x-1)log5
xlog3+4log3=xlog5-1log5
4log3+1log5=xlog3-xlog5
x=4*0.47712+1*0.69897/0.69897-0.47712
Question 145713: Please help me solve this problem
3^x+4=5^x-1
(x+4)log3=(x-1)log5
xlog3+4log3=xlog5-1log5
4log3+1log5=xlog3-xlog5
x=4*0.47712+1*0.69897/0.69897-0.47712
You can put this solution on YOUR website! There is a small error in step 4:
3^x+4=5^x-1
(x+4)log3=(x-1)log5
xlog3+4log3=xlog5-1log5
4log3+1log5=xlog3-xlog5 SHOULD BE 4log3 + 1 log 5= xlog5 - x log 3
Next, factor the x from the right side of the equation:
4log3 + 1 log 5= x(log5 - log 3)
Last, divide both sides by (log5 - log3)
Can you use a calculator to calculate this?? I get x=11.75.
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