SOLUTION: How do you Plot the graphs of the following functions 1. (x)=6x 2. f(x)=3x - 2 3. f(x)=(1/2)x 4. f(x)= log2x
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-> SOLUTION: How do you Plot the graphs of the following functions 1. (x)=6x 2. f(x)=3x - 2 3. f(x)=(1/2)x 4. f(x)= log2x
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Question 145504
:
How do you Plot the graphs of the following functions
1. (x)=6x
2. f(x)=3x - 2
3. f(x)=(1/2)x
4. f(x)= log2x
Answer by
jim_thompson5910(35256)
(
Show Source
):
You can
put this solution on YOUR website!
I'll do the first two to get you started
# 1
Looking at
we can see that the equation is in slope-intercept form
where the slope is
and the y-intercept is
note:
really looks like
Since
this tells us that the y-intercept is
.Remember the y-intercept is the point where the graph intersects with the y-axis
So we have one point
Now since the slope is comprised of the "rise" over the "run" this means
Also, because the slope is
, this means:
which shows us that the rise is 6 and the run is 1. This means that to go from point to point, we can go up 6 and over 1
So starting at
, go up 6 units
and to the right 1 unit to get to the next point
Now draw a line through these points to graph
So this is the graph of
through the points
and
# 2
Looking at
we can see that the equation is in slope-intercept form
where the slope is
and the y-intercept is
Since
this tells us that the y-intercept is
.Remember the y-intercept is the point where the graph intersects with the y-axis
So we have one point
Now since the slope is comprised of the "rise" over the "run" this means
Also, because the slope is
, this means:
which shows us that the rise is 3 and the run is 1. This means that to go from point to point, we can go up 3 and over 1
So starting at
, go up 3 units
and to the right 1 unit to get to the next point
Now draw a line through these points to graph
So this is the graph of
through the points
and