SOLUTION: Divide the following expression 27z+23z^2+6z^3 /(over) 2z+3

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Question 145483: Divide the following expression 27z+23z^2+6z^3 /(over) 2z+3
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
%286z%5E3+%2B+23z%5E2+%2B+27z%29+%2F+%282z+%2B+3%29
The 1st term of the answer is 3z%5E2 since
3z%5E2%2A%282z+%2B+3%29+=+6z%5E3+%2B+9z%5E2
6z%5E3+%2B+23z%5E2
-6z%5E3+-+9z%5E2
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14z%5E2
The 2nd term of the answer is 7z since
7z%2A%282z+%2B+3%29+=+14z%5E2+%2B+21z
14z%5E2+%2B+27z
-14z%5E2+-+21z
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6z (remainder)
So, the complete answer is
3z%5E2+%2B+7z+%2B+%286z%2F%282z+%2B+3%29%29
You can check this by multiplying it by 2z+%2B+3