SOLUTION: ((2x^2-8)/(2x^2-x-1)/(8x^2-12x-8)/(x^2-1))

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: ((2x^2-8)/(2x^2-x-1)/(8x^2-12x-8)/(x^2-1))       Log On


   

Question 145430This question is from textbook intermediate algebra
: ((2x^2-8)/(2x^2-x-1)/(8x^2-12x-8)/(x^2-1))
This question is from textbook intermediate algebra

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
%28%282x%5E2-8%29%29%2F%28%282x%5E2-x-1%29%29
---------------
%28%288x%5E2-12x-8%29%29%2F%28%28x%5E2-1%29%29
:
factor
%282%28x%5E2-4%29%29%2F%28%282x%2B1%29%28x-1%29%29%29
---------------
%284%282x%5E2-3x-2%29%29%2F%28%28x-1%29%28x%2B1%29%29
:
Factor some more
%282%28x-2%29%28x%2B2%29%29%2F%28%282x%2B1%29%28x-1%29%29%29
---------------
%284%282x%2B1%29%28x-2%29%29%2F%28%28x-1%29%28x%2B1%29%29
:
Invert the dividing fraction and multiply:
%282%28x-2%29%28x%2B2%29%29%2F%28%282x%2B1%29%28x-1%29%29%29 * %28%28x-1%29%28x%2B1%29%29%2F%284%282x%2B1%29%28x-2%29%29
:
Cancel: 2 into 4, (x-2)'s; (x-1)'s
%28%28x%2B2%29%29%2F%28%282x%2B1%29%29 * %28%28x%2B1%29%29%2F%282%282x%2B1%29%29 = %28%28x%2B2%29%28x%2B1%29%29%2F%282%282x%2B1%29%5E2%29