SOLUTION: Write an equation in slope-intercept form of a line that passes through the points, (2, -2) and is perpindicular to the graph of x+5y=6

Algebra ->  Rational-functions -> SOLUTION: Write an equation in slope-intercept form of a line that passes through the points, (2, -2) and is perpindicular to the graph of x+5y=6      Log On


   

Question 14542: Write an equation in slope-intercept form of a line that passes through the points, (2, -2) and is perpindicular to the graph of x+5y=6
Answer by Alwayscheerful(414) About Me  (Show Source):
You can put this solution on YOUR website!
In order to find the slope of a line perpendicular to another, you need to take the negative recipricol. In your case, you first need to transform it to y=mx+b form. You do that by isolating the y and solving.
5y=-x%2B6
y=%28-1%2F5%29x%2B6%2F5
So, we wee that your slope is -1%2F5x.
The negative recipricol is 5x.
Then, all you do is plug in 2 for your x value and -2 for you y and solve for b.
-2=5%282%29%2Bb
-2=10%2Bb
-12=b
The final equation should be
y=5x-12
Hope this helps!